General Social/Chatter Thread

[The Rock Doctor]

Perhaps Parthia and Japan should fight for the honor.

[Kaiser Kirk]

Perhaps Parthia and Japan should fight for the honor.

There's no need for that.
There's the difference that Parthia shares a land border with the Golden Horde and has a large deployable army which could come to Wilno's aide.
Japan... not so much.
:)

But, glad to hear Wilno is considering the concept !

[The Rock Doctor]

I'm playing with an inclined belt for a 1918 design.

But I have forgotten virtually everything I ever learned about trigonometry.

If a belt is inclined at 10 degrees, and is to full enclose a space 4.8 metres high, how "high" does the actual belt need to be?

[Kaiser Kirk]

Hmm, I actually had to use trig a couple years ago to figure out offset angles setting up cable yarding corridors...
but there, I know adjacent and opposite and am trying to find the angle correction...
This is adjacent (4.8m) and angle are known and we want hypotenuse.

..which I didn't remember...and had to look it up

Cos (deg) = Adjacent/hypotenuse

So

Cos (10) = 0.98480775301221  = 4.8 / hypotenuse

So

hypotenuse * 0.98480775301221 = 4.8

so

hypotenuse = 4.8 / 0.98480775301221  = 4.874

hmm not as big a difference as expected, perhaps I made an error, but luckily I showed my work so others can find it !!!

[Desertfox]

It's a very shallow angle so your math looks good. Unless your calculator is set to radians instead of degrees.

[The Rock Doctor]

Thanks for that, Kirk.

I found a site this morning that confirmed the same number, so that's handy.  I was not expecting a huge difference from 4.8 metres, but maybe a bit more than a 7.5 cm difference.

[Kaiser Kirk]

I think for Parthians that math should work
For all others, just double the distance to be covered...
::)

[The Rock Doctor]

For a given vertical height, the length of the hypotenuse/angled belt is:

10 degrees:  101.5%
12 degrees:  102.2%
14 degrees:  103.1%
16 degrees:  104.0%
18 degrees:  105.2%
20 degrees:  106.4%

[The Rock Doctor]

I'm starting to feel like eight destroyers a year is too many.  That's 160 over a twenty year period.

[Jefgte]

I'm starting to feel like eight destroyers a year is too many.  That's 160 over a twenty year period.

6 is a good medium number.
12 per year => 1 Flotilla per year.

You could reduce to 4 if you built Torpedo Boat or TGB for coastal operation.

(TGBs only have 50% of the displacement reserved for the engines.
Weight saving is reserved for the installation of a powerful artillery, often 120mm guns and 4 torpedo tubes.)

[Desertfox]

Psh, I only laid down 16 destroyers this half year, while reffiting another 8.

[The Rock Doctor]

Slacker.

[TacCovert4]

Slacker.

Sad GTB noises. 

1918 I will build 4 x DDs......just saying. 

[The Rock Doctor]

Halving my destroyer build only nets me tonnage for two capital ships, though.  Still spending most of my tonnage on the big boys.

[Jefgte]

Halving my destroyer build only nets me tonnage for two capital ships, though.  Still spending most of my tonnage on the big boys.

What is the best fleet ratio?
1BB
1AC
2CL
3DD (ocean operations)
2TB (coastal operations)

1 or 1.5...2 or 2.5...?